Determining
Space
Thickness Given
Dimensions Under
Pins or Balls
|
| TO
GET |
HAVING |
RULE |
FORMULA |
| N |
Number
of teeth |
Given |
60 |
| DP |
Normal
diametral pitch |
24 |
| |
Normal
pressure angle |
22.5 |
| h |
Pitch
helix angle |
7.50000 |
| d |
Ball
diameter |
0.07377 |
| DE |
Dimension
under balls even # of teeth |
2.41200 |
| DO |
Dimension
under balls odd # of teeth |
******* |
| αd |
Transverse
pressure angle |
TAN(αd)=TAN(αn)/COS
(h) |
22.67458 |
| H |
Base
helix angle |
TAN(H)=TAN(h)•COSαd |
6.92618 |
| dD |
Transverse
ball diameter |
d/COS(H) |
0.07431 |
| PD |
Pitch
diameter |
N/[DP•COS(h)] |
2.52157 |
| BD |
Base
diameter |
PD•COS(αd) |
2.32668 |
| CE |
Twice
the center distance of ball and gear even # of teeth |
DE+d |
2.48577 |
| CO |
Twice
the center distance of ball and gear odd # of teeth |
(DO+d)/COS(90/N) |
******* |
| β |
Pressure
angle to ball center |
COS(β)=BD/CE
or CO |
20.60986 |
| INVβ |
Involute
function of β |
TAN(β)-[β(p/180)] |
0.01636 |
| INVαd |
Involute
function of ad |
TAN(αd)-[αd(p/180)] |
0.02204 |
| D |
|
dD/BD |
0.03194 |
| sd |
Transverse
arc space width |
PD•(INVβ+DINVαd) |
0.06621 |
| sn |
Normal
arc space width |
sd•COS(h) |
0.06565 |
|