| TO GET |
HAVING |
RULE |
FORMULA |
| N |
Number of teeth |
Given |
16 |
| DP |
Normal diametral
pitch |
6 |
| h |
Pitch helix angle |
12.16370 |
| αn |
Normal pressure
angle |
25 |
| sn |
Normal arc space
width |
0.26220 |
| d |
Ball diameter |
0.24000 |
| αd |
Transverse pressure
angle |
TAN(αd)=TAN(αn)/COS(h) |
25.50193 |
| sd |
Transverse arc
space width |
sn/COS(h) |
0.26822 |
| H |
Base helix angle |
TAN(H)=TAN(h)•COSαd |
11.00905 |
| dD |
Transverse ball
diameter |
d/COS(H) |
0.24450 |
| PD |
Pitch diameter |
N/[DP•COS(h)] |
2.72791 |
| BD |
Base diameter |
PD•COS(αd) |
2.46213 |
| INVαd |
Involute function
of ad |
TAN(αd)-[αd(π/180)] |
0.03192 |
| A |
|
sd/PD |
0.09833 |
| dD |
|
dD/BD |
0.09930 |
| INVβ |
Involute function
of β |
A+INVαd-D |
0.03095 |
| β |
Pressure angle to
ball center |
see tables page G14 |
25.25264 |
| CC |
Twice the center
distance of ball and gear |
BD/COS(β) |
2.72229 |
| DE |
Dimension under
balls even # of teeth |
CC-d |
2.48229 |
| DO |
Dimension under
balls odd # of teeth |
CC•COS(90/N)-d |
******** |
| Φ |
Pressure angle to
point of tangency |
TAN(Φ)=TAN(β)+[d•COS(H)/BD] |
29.56926 |
| RT |
Radius to point of
tangency |
BD/[2•COS(Φ)] |
1.41541 |
